Thursday, November 14, 2013

reorder list@leetcode

刷题必备书籍Cracking the Coding Interview: 150 Programming Questions and Solutions 

简历:The Google Resume: How to Prepare for a Career and Land a Job at Apple, Microsoft, Google, or any Top Tech Company
算法学习书籍:Introduction to Algorithms
编程珠玑:Programming Pearls (2nd Edition)
C++ 学习:The C++ Programming Language, 4th Edition
经典操作系统书籍,龙书:Operating System Concepts
创业:The Start-up of You: Adapt to the Future, Invest in Yourself, and Transform Your Career
Given a singly linked list LL0L1→…→Ln-1Ln,
reorder it to: L0LnL1Ln-1L2Ln-2→…
You must do this in-place without altering the nodes' values.
For example,
Given {1,2,3,4}, reorder it to {1,4,2,3}.
Basic idea,
1. get length of the linked list
2. go to the middle node of the list
3. reverse the bottom part of the list, set NULL to last node of upper part list, and NULL to the first node of bottom part list
4. insert one by one
Pay attention to the corner case. One is when we have odd number of elements in list, we have one node more in bottom part.  The other case is we have only one node in bottom part when reversing.

2 comments:

Leetcode 316. Remove Duplicate Letters

 这道题表面问的是如何删除重复,实际在问如何从多个字符选取一个保留,从而让整个字符串按升序排列。那么策略就是对于高顺位的字符比如‘a',就要选靠前位置的保留,而低顺位字符如’z'则应该尽量选取靠后位置保留。 算法大概思路:每看到一个字符,我们要决定是否保留 1. ...