Wednesday, October 2, 2013

3 Sum Closest@leetcode

刷题必备书籍Cracking the Coding Interview: 150 Programming Questions and Solutions 

简历:The Google Resume: How to Prepare for a Career and Land a Job at Apple, Microsoft, Google, or any Top Tech Company
算法学习书籍:Introduction to Algorithms
编程珠玑:Programming Pearls (2nd Edition)
C++ 学习:The C++ Programming Language, 4th Edition
经典操作系统书籍,龙书:Operating System Concepts
创业:The Start-up of You: Adapt to the Future, Invest in Yourself, and Transform Your Career

3Sum Closest

 
AC Rate: 545/1778
My Submissions
Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
    For example, given array S = {-1 2 1 -4}, and target = 1.

    The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).

和3 sum几乎一样,用一个variable来record target - sum的绝对值,一直变动。但要注意的是:一旦遇到sum == target的,要break!

1 comment:

Leetcode 316. Remove Duplicate Letters

 这道题表面问的是如何删除重复,实际在问如何从多个字符选取一个保留,从而让整个字符串按升序排列。那么策略就是对于高顺位的字符比如‘a',就要选靠前位置的保留,而低顺位字符如’z'则应该尽量选取靠后位置保留。 算法大概思路:每看到一个字符,我们要决定是否保留 1. ...