Saturday, July 20, 2013

Binary Tree Level Order Traversal @leetcode

刷题必备书籍Cracking the Coding Interview: 150 Programming Questions and Solutions 

简历:The Google Resume: How to Prepare for a Career and Land a Job at Apple, Microsoft, Google, or any Top Tech Company
算法学习书籍:Introduction to Algorithms
编程珠玑:Programming Pearls (2nd Edition)
C++ 学习:The C++ Programming Language, 4th Edition
经典操作系统书籍,龙书:Operating System Concepts
创业:The Start-up of You: Adapt to the Future, Invest in Yourself, and Transform Your Career
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level).
For example:
Given binary tree {3,9,20,#,#,15,7},
    3
   / \
  9  20
    /  \
   15   7
return its level order traversal as:
[
  [3],
  [9,20],
  [15,7]
]
confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ.
» Solve this problem

这题就是BFS,不论是图还是树的一种基本遍历的方法,应该掌握,比较简单,我用了2个queue来存,其实不需要,用一个count来计数每一层的node的个数,我使用了一个queue在level order traversal ii里面。


1 comment:

  1. I always thought of using two queues or vectors. Never thought of using only one queue with simply counters. Grateful for being inspired by your blog. Thanks.

    ReplyDelete

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