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Given an array and a value, remove all instances of that value in place and return the new length.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
» Solve this problemTo search from the end of the array. Once find a element whose value equals to the target, then move all the elements after current element one step further.
一个果断比我好很多简洁很多的代码，和remove duplicate的思路是一样的。。。。我要学会。。。嗯嗯
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